lf x-1/x=6,find x²+1/x²
Answers
Answered by
0
Answer:
34
Step-by-step explanation:
(x-1/x)^2 =x^2 +(1/x)^2 -2
6^2 = x^2 +(1/x)^2 -2
36 -2 =x^2+ (1/x)^2
34 = x^2 + (1/x)^2
Answered by
1
Answer:
Given: x - 1/x = 6
To find: x^2 + 1/x^2 = ?
We know that,
(a-b)^2 = a^2 + b^2 - 2ab
We will use this identity to find the value of x^2 + 1/x^2.
=> (x - 1/x)^2 = x^2 + (1/x)^2 - 2•x•(1/x)
=> (x - 1/x)^2 = x^2 + 1/x^2 - 2
=> (6)^2 = x^2 + 1/x^2 - 2
{ given: x - 1/x = 6 }
=> 36 = x^2 + 1/x^2 - 2
=> x^2 + 1/x^2 = 36 + 2
=> x^2 + 1/x^2 = 38
Thus, the required value of x^2 + 1/x^2 is
38.
Similar questions