lf x+y=8 and xy=2, find the value of 2x^2+2y^2
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Answer:
x + y = 8 (eq1)
x - y = 2 (eq2)
adding both equation we get
2x = 10
x = 5
putting the value in eql we get
y=8-5
y = 3
now
=> 2x² +2y²
=> 2(5)² + 2(3)²
=> 2 x 25 + 2 × 9
=> 50 + 18
=> 68
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