Question

lf x+y+z=0 ,then show that x cube +y cube+z cube= 3xyz​

Answer 1

Answer:

Ok I have done

Step-by-step explanation:

Answer 2

SOLUTION:-

Given:

x+ y+z= 0.

So,

x+ y = (-z)

Cubic on both sides:

=) (x+y)³ = (-z)³

=) x³ +y³ +3xy(x+y) =(-z)³

=) x³ +y³ +z³ = -3xy(x+y)

&

x + y= -z

Putting in the value of x+y

=) x³ +y³ + z³ = -3xy(-z)

=) x³ + y³ +z³ = 3xyz

Hence,

Proved.

Hope it helps ☺️