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nevermind answer this:
write a numpy program to create a 8x8 matrix and fill it with a checkboard pattern:
[[0 1 0 1 0 1 0 1]
[0 1 0 1 0 1 0 1]
[0 1 0 1 0 1 0 1]
[0 1 0 1 0 1 0 1]
[0 1 0 1 0 1 0 1]
[0 1 0 1 0 1 0 1]
[0 1 0 1 0 1 0 1]
[0 1 0 1 0 1 0 1]]
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4
Answer:
import numpy as np
x = np.ones((3,3))
print("Checkerboard pattern:")
x = np.zeros((8,8),dtype=int)
x[1::2,::2] = 1
x[::2,1::2] = 1
print(x)
Answered by
4
import numpy as np
x = np.ones((3,3))
print("Checkerboard pattern:")
x = np.zeros((8,8),dtype=int)
x[1::2,::2] = 1
x[::2,1::2] = 1
print(x)
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