Light falls from glass (μ= 1.5) to air. Find the angle of incidence for which the angle of deviation is 90°.
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Answered by
7
Given :
μ= 1.5
d= 90°
critical angle = sin ⁻¹(1/(μ )= 41.80
maximum deviation which is possible is = 90- 41,80=47.2°
so in the gase case total internal reflection ust have taken place
deviation = 180- 2i=90
2i=90
i=45°
Answered by
2
Answer is given below..
μ= 1.5
d= 90°
critical angle = sin ⁻¹(1/(μ )= 41.80
maximum deviation which is possible is = 90- 41,80=47.2°
so in the gase case total internal reflection ust have taken place
deviation = 180- 2i=90
2i=90
i=45°
μ= 1.5
d= 90°
critical angle = sin ⁻¹(1/(μ )= 41.80
maximum deviation which is possible is = 90- 41,80=47.2°
so in the gase case total internal reflection ust have taken place
deviation = 180- 2i=90
2i=90
i=45°
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