Question

light is incident on a transparent glass slab at an angle of 37 degrees. the speed of light in glass slab is found to be C/3 where C is the speed of light in air or vacuum. the angle of refraction in the medium is​

Answer 1

Answer:

r = 11.57°            

Explanation:

given,                                

Speed of incident ray = c

speed in the glass = c/3

where c is speed of light

angle of refraction = ?        

angle of incident = 37°

refractive index in air = n₁ = 1

n₂ = ?                                    

using snells law                          

$\dfrac{sin\ i}{sin\ r} = \dfrac{v_1}{v_2}$

$\dfrac{sin\ 37^0}{sin\ r} = \dfrac{c}{\dfrac{c}{3}}$

$\dfrac{0.602}{sin\ r} = 3$

$sin r = \dfrac{0.602}{3}$

$sin r = 0.20$

$r = sin^{-1}(0.20)$

r = 11.57°