Question

Light of wavelength 4000angstrom falls on the surface of cesium .Calculate the energy if the photoelectron emitted. The critical wavelength for photoelectric effect is 6600angstrom.

Answer 1

Light of wavelength is 4000 angstrom

By using the formula Hf = K + W

K = hf - W

K = hc * (1/λ - 1/λo)

K = 12400 eV Å * (1/ (4000 Å) - 1/ (6600 Å) )

K = 1.22 eV

Therefore, answer: - Kinetic energy of photoelectrons emitted is 1.22 eV

Answer 2

The correct  answer....