Light ray refracts into a medium. The angle of deviation is 150. Find the refractive index u
15⁰
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Answer:
Let the refractive index of the medium be n and speed of light in air is c.
Using Snell's law of refraction : n
air
×sini=n
medium
×sinr where n
air
=1
∴ 1×sini=n×sinr ⟹n=
sinr
sini
Velocity of light in a medium v=
n
c
=
sini
c×sinr
⟹v∝sin r
Thus velocity of light is minimum in medium A.
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