Light travels through glycerine with a speed of 2.05×10^8 m/s . Find the refractive index of glycerine . Given speed of light in vaccum = 3×10^8 m/s
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Answered by
17
Hi !
Refractive index = speed of light in vacuum/speed of light in the medium
= 3 × 10⁸ /2.05× 10⁸
= 1.4634 [ approx.]
Refractive index = speed of light in vacuum/speed of light in the medium
= 3 × 10⁸ /2.05× 10⁸
= 1.4634 [ approx.]
Answered by
8
Speed of light in vacuum (c) = 3 * 108
Speed of light in glycerin (s) = 2.05 * 108
Now, Absolute Refractive index (n) = c/s
So, Absolute Refractive Index of glycerin = 3 * 108 / 2.05 * 108 = 1.463
Speed of light in glycerin (s) = 2.05 * 108
Now, Absolute Refractive index (n) = c/s
So, Absolute Refractive Index of glycerin = 3 * 108 / 2.05 * 108 = 1.463
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