lim ₓ→₁₋ [√π – √(2sin⁻¹ x)]/√(1 – x)
is equal to :
(A) 1/√(2π)
(B) √(2/π)
(C) √(π/2)
(D) √(π)
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Question ;
lim ₓ→₁₋ [√π – √(2sin⁻¹ x)]/√(1 – x)
It is an 0/0 form
so for solving the question , we use L- Hospital rule .
For step by step explanation refer to the attachment.
correct option b)
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