Question

lim (1 + sin x)cot x is equal to
x=0​

Answer 1

Answer:

$0$

Step-by-step explanation:

$lim \: \: \: \: (x = 0) \: \: \: \: \: \frac{1 + \sin(x) }{ \cot(x) } =lim(x = 0) \: \: \: \: \: \: \frac{ \cos(x) }{ - { \csc(x) }^{2} } \\ \\ = lim(x = 0) \: \: \: \: \: \: ( - \cos(x) \sin(x) ) \\ \\ \\ = - \cos(0) \sin(0) = - 1 \times 0 = 0 \\ \\ = 0$