lim {cosec(x) - cot(x)}
x-1
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first of all please correct your question ;
lim {cosec(x) - cot(x)}
x->0
now ;
1/sinx - cosx/sinx
(1-cosx)/sinx
when we put x=0
then we get 0/0 form .
so as we know for 0/0 form use D-L hospital rule :
d/dx ( 1-cosx) / d/dx(sinx)
= ( 0+sinx ) / cosx
= Sin (0) / cos (0)
= 0/1
= 0
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