lim h tends to 0 e[ (x+h)^2-e^(x^2)]÷h
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jdjejdjdid Given height of the cylinder, h = 1 m
Capacity of the cylinder = 15.4 litres
V = 0.001 x 15.4 = 0.0154 cu m
That is πr2h = 0.0154
r2 = (0.0154 x 7) / (22 ) = 0.0049
Hence r = 0.07 m
Total surface area = 2πr(r + h)
= 2 x (22/7) x (0.07)(0.07 + 1)
= 0.4708 sq m
Capacity of the cylinder = 15.4 litres
V = 0.001 x 15.4 = 0.0154 cu m
That is πr2h = 0.0154
r2 = (0.0154 x 7) / (22 ) = 0.0049
Hence r = 0.07 m
Total surface area = 2πr(r + h)
= 2 x (22/7) x (0.07)(0.07 + 1)
= 0.4708 sq m
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