Question

lim tanx/sinx and x approaches to 0

Answer 1

tanx−sinxx3=sinxx31−cosx cosx. tanx−sinxx3=(sinxx)(1−cosxx2)(1cosx). We can use now the well known trigonometric limit: limx→0sinxx=1. and using the ...

Answer 2

Tanx /sinx = 1/cosx, = sec x.

So lim tanx/sinx where x tends to 0
So, lim x->0 secx = sec 0 = 1
Hope this is ur required answer.