Lim tends to thita_0
Thita ÷ under root 1- cos this
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Heya!!!
x = theta
lim. x / √ ( 1 - cos x )
x--->0
lim. x / √ ( 2 Sin² x/2 )
x--->0
lim. 1 / √2 { x / Sin x / 2 }
x--->0
lim. 1 / √2 { x / 2 / Sin ( x / 2 ) } × 2
x--->0
= 2 / √2 = √2
x = theta
lim. x / √ ( 1 - cos x )
x--->0
lim. x / √ ( 2 Sin² x/2 )
x--->0
lim. 1 / √2 { x / Sin x / 2 }
x--->0
lim. 1 / √2 { x / 2 / Sin ( x / 2 ) } × 2
x--->0
= 2 / √2 = √2
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