lim teta→0 sin m square teta/teta equal to
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Answer:
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Explanation:
I am taking thetha as x for convenience
= lim (x to 0) (Sin²x)/(x)
= lim. (x to 0) (sinx)/(x) * (sin x)
= lim (x to 0)( sinx)/x) × (lim x to 0) sinx. (we can seperate because sinx is continuous through the limit)
= 1 × 0 = 0
(OR)
lim x to 0) (sinx)/(x)
is 0/0 indeterminate, so we can use L'Hopital Rule,
= (lim x to 0) (2 sinx cos x)/1)
= 0
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