Math, asked by rlthulasiram08, 6 months ago

Lim x-0. |sin x|/sin x

Answers

Answered by kiranshukla84626
0

Answer:

Difference Between

Translucent, Transparent, and

Opaque Materials. ...

Transparent objects allow all the light to pass through them, translucent ones allow partial light to pass, whereas opaque ones allow no light to pass through.

Answered by NITESH761
0

Answer:

Limit does not exist.

Step-by-step explanation:

We have,

\displaystyle \sf \lim_{x \to 0} \dfrac{| \sin x |}{\sin x}

Calculate left hand limit,

\displaystyle \sf \lim_{x \to 0^{-}} \dfrac{( \sin x) }{- (\sin x)} = -1

Now, Calculate right hand limit,

\displaystyle \sf \lim_{x \to 0^{+}} \dfrac{( \sin x )}{ (\sin x)} = 1

As LHL ≠ RHL, Limit does not exist.

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