Question

lim x-0 sin2x/3-√2x+9​

Answer 1

Answer:

Step-by-step explanation:

Lim x--)0 sin2x/ 3-√2x+9 x 3+√2x+9/3+√2x+9

lim x--)0  sin 2x ( 3+√2x+9)/9 - (2x+9)

lim x--)0 sin2x( 3+√2x+9)/2x

lim x---)0 sin 2x/-2x  x 3+√2(0) + 9

= -1 x 3+3

=-6