Math, asked by ritika4991, 1 month ago

lim x-2
 \frac{ (\sqrt[5]{x}  +  \sqrt[5]{2} )( \sqrt[5]{x}  -  \sqrt[5]{2} )}{x - 2}

Answers

Answered by aurelinasingh2006
0

Answer:

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Step-by-step explanation:

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Answered by Charithaar
1

Step-by-step explanation:

as it is 0/0 form

we can write it as

= x^(2/5) - 2^(2/5) / x-2

let's apply the L-hospital rule

= (2/5)x^(-3/5) / 1

= 2/5x^(3/5)

now apply limit x tends to 2

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