lim x-2 x cube+4x - 16 / 2x cube - 3x - 10
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find the factors of numerator and denominator
x^3+4x-16 =(x-2)(x^2+2x+8)
2x^3-3x-10=(x-2)(2x^2+4x+5)
after cancellation
limx tends 2 (x^2+2x+8)/(2x^2+4x+5)
=(2^2+2*2+8)/(2*2^2+4*2+5)
=(4+4+8)/(8+8+5)
=16/23
x^3+4x-16 =(x-2)(x^2+2x+8)
2x^3-3x-10=(x-2)(2x^2+4x+5)
after cancellation
limx tends 2 (x^2+2x+8)/(2x^2+4x+5)
=(2^2+2*2+8)/(2*2^2+4*2+5)
=(4+4+8)/(8+8+5)
=16/23
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