Question

lim x→-2 (x³+x²+4x+12)+(x³-3x+2)

Answer 1

by adding we get
X^3 + X ^2 + X +2
not put X = -2
(-2)^3 + (-2) ^2 +(-2) +2
-8+4-2+2
-4

Answer 2

Answer:

lim x→-2 (x³ + x² + 4x + 12) + (x³ -3x + 2) Answer of it is 0

Step-by-step explanation:

In the limit question we should know the rule that limit approaches means that the limit is quietly near to that value but not that value so in this question limit is approaching to -2

so to find the value of the polynomial function we will plug in the -2 for the answer

Now given polynomial is

(x³ + x² + 4x + 12) + (x³ -3x + 2)

lim x → -2

Putting x = -2 in the given polynomial which is

=(x³ + x² + 4x + 12) + (x³ -3x + 2)

putting x= -2

=((-2)³ + (-2)² + 4(-2) + 12) + ((-2)³ -3(-2) + 2)

Solving it

= (-8 + 4 -8 +12) + (-8 + 6 + 2)

= ( -4 +4)+ (-8 + 8)

adding gives

= (0)+(0)

So it

= 0

So the answer is 0