Question

lim x➡️3 (2x^2+3x+1) / (x+2)

Answer 1

sᴏʟᴜᴛɪᴏɴ

lim X tends to 3

$\frac{2x {}^{2} + 3x + 1}{x + 2}$

it's is not indeterminate form

so simply put X = 3 in the given expression

then answer is

28/5

I hope it helps you

follow me

Answer 2

Answer:

$\large\bold\red{\frac{28}{5}}$

Step-by-step explanation:

we have to find,

$\lim_{x \to 3} \frac{2 {x}^{2} + 3x + 1}{x + 2}$

Now,

putting x = 3

we observe that,

its not in indeterminate form like 0/0 , ∞/∞

therefore,

we have to simply put the value x = 3

Therefore,

we get,

$\lim_{x \to 3} \frac{2 {x}^{2} + 3x + 1 }{x + 2} \\ \\ = \frac{2 \times {3}^{2} + 3 \times3 + 1 }{3 + 2} \\ \\ = \frac{(2 \times 9) + (3 \times 3) + 1}{(3 + 2)} \\ \\ = \frac{18 + 9 + 1}{5} \\ \\ = \frac{28}{5}$

Hence,

the value of given limit is $\bold{\frac{28}{5}}$