Question

Lim x -->0 sin log(1+x)/log(1+x)​

Answer 1

Answer:

lim x->0 sinlog(1+x)/log(1+x)

usine Leibniz rule

lim x->0 coslog(1+x)*(1/(1+x) ) / [1/(1+x) ]

put limit

=coslog(1+0)*1/(1+0) / [1/(1+0) ]

=cos(log1)/1

=cos(0)

=1