Question

lim x>0
[sinx + cosx]

Answer 1

Answer:

1

Explanation:

sinx

cosx

Divide numerator and denominator by

Cancelling:

sinxxcosx

1limx→0 (sinxxcosx)

=limx--- 0 (sinx)

⋅

limx→0

(cosx)

limx→0(sinx)=1

limx→0(cosx)=1×1=1

∴

limx→0

(sin

xcos

xx

)=1