lim
x-->0
![\frac{ {e}^{x} + {e}^{ - x} - 2 }{ {x}^{2} } \frac{ {e}^{x} + {e}^{ - x} - 2 }{ {x}^{2} }](https://tex.z-dn.net/?f=+%5Cfrac%7B+%7Be%7D%5E%7Bx%7D+%2B++%7Be%7D%5E%7B+-+x%7D++-+2+%7D%7B+%7Bx%7D%5E%7B2%7D+%7D+)
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Answered by
1
Answer:
differentiate on each stage to make the denominator independent of x.
so that you won't get 0/0 form.
Ans: 1
check the attachment for the complete answer...
hope this helps you...
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Answered by
1
Answer:
1
Step-by-step explanation:
Step 01:- first of all find the form which is 0/0 form
step 02:- using l' hospital rule Diffrentiating with respect to X sperately numerator and denominator .
Step 03 :- form doesn't change so again Diffrentiating with respect to X.
step 04:- then put the limit.
_____________________________
Solution is in this given attachment .
Hope it's helpful
Attachments:
![](https://hi-static.z-dn.net/files/d5e/9ab558e8f019fe0da7a40779bd81dbd5.jpg)
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