Math, asked by DhairyaPanchal, 2 months ago

lim x —> 0, x / √a+x - √a-x​

Answers

Answered by senboni123456
0

Step-by-step explanation:

We have,

 \lim_{x \rarr0 } \frac{x}{ \sqrt{a + x} -  \sqrt{a - x}  }  \\

 \implies\lim_{x \rarr0 } \frac{x( \sqrt{a + x} +  \sqrt{a - x} ) }{a + x - a + x}  \\

 \implies\lim_{x \rarr0 } \frac{x( \sqrt{a + x}  +  \sqrt{a - x}) }{2x}  \\

 \implies\lim_{x \rarr0 } \frac{ \sqrt{a + x}  +  \sqrt{a - x} }{2}  \\

  =  \frac{ \sqrt{a + 0}  +  \sqrt{a - 0} }{2}  \\

 =  \frac{2 \sqrt{a} }{2}  \\

 =  \sqrt{a}

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