Math, asked by lmpatilplane, 26 days ago

lim
x-> π/2
tan 2x
x-π/2

Answers

Answered by purvigarg034

0

Answer:

lim

x→

2

π

x−

2

π

tan2x

LHL=lim

h→0

−

2

π

−h−

2

π

tan2(

2

π

−h)

=lim

h→0

−

−h

tan(π−2h)

=lim

h→0

−

−

−h

tan2h

=lim

h→0

−

−

−2h

2tan2h

=2

RHL=lim

h→0

+

2

π

+h−

2

π

tan2(

2

π

+h)

=lim

h→0

+

h

tan(π+2h)

=lim

h→0

+

h

tan2h

=lim

h→0

+

2h

2tan2h

=2

Thus,lim

x→

2

π

x−

2

π

tan2x

=2

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