Math, asked by helpme555, 11 months ago

lim x-> 2 x^7-128/x^6-64 (trigonometry) no spam

Answers

Answered by Anonymous
10
\sf{\underline{\underline{Question:}}}


\boxed{ \displaystyle \lim_{x \to 2} \frac{x^{7}-128}{x^{6}-64}}


\sf{\underline{\underline{Solution}}}:


= \displaystyle \lim_{x \to 2} \frac{x^{7}-128}{x^{6}-64}


= \displaystyle \lim_{x \to 2} \frac{x^{7}-2^{7}}{x^{6}-2^{6}}


= \displaystyle \lim_{x \to 2}  \frac{ \frac{ {x}^{7} - {2}^{7} }{x - 2} }{ \frac{ {x}^{6} - {2}^{6} }{x - 2} }


 = \frac{\displaystyle \lim_{x \to 2} \frac{x^{7}-2^{7}}{x - 2}}{\displaystyle \lim_{x \to 2} \frac{x^{6}-2^{6}}{x - 2}}


 = \frac{7 \times {2}^{6} }{6 \times {2}^{5} }


 = \frac{7}{6} \times {2}^{6 - 5}


 = \frac{7}{6} \times 2


 =\boxed{ \frac{7}{3}}


\sf{\underline{Answer}}: \boxed{ \frac{7}{3}}

helpme555: Yes 7/3 is the right answer
Anonymous: :)
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