Question

lim x tends 3[x*2+2x-15/x*2-5x+6=​

Answer 1

Answer:

$\displaystyle \boxed{{ \lim_{x \to 3} \frac{x^2+2x-15}{x^2-5x+6} =8}}$

Step-by-step explanation:

Given :

$\displaystyle{ \lim_{x \to 3} \frac{x^2+2x-15}{x^2-5x+6} }$

On solving it further :

$\displaystyle{ \lim_{x \to 3} \frac{x^2+2x-15}{x^2-5x+6} }\\\\\\\displaystyle{\rightarrow \lim_{x \to 3} \frac{x^2+5x-3x-15}{x^2-3x-2x+6} }\\\\\\\displaystyle{\rightarrow \lim_{x \to 3} \frac{x(x+5)-3(x+5)}{x(x-3)-2(x-3)} }\\\\\\\displaystyle{\rightarrow \lim_{x \to 3} \frac{(x-3)(x+5)}{(x-3)(x-2)} }$

Here ( x - 3 ) get cancel out we get :

$\displaystyle{\rightarrow \lim_{x \to 3} \frac{(x+5)}{(x-2)} }$

Now putting x = 3

$\displaystyle{\rightarrow \lim_{x \to 3} \frac{(x+5)}{(x-2)} }\\\\\\\displaystyle{\implies \frac{3+5}{3-2} }\\\\\\\displaystyle {\implies 8}$

Hence we get answer.

Answer 2

Answer:

I hope answer is helpful to us