lim x tends to 0 (cosecx-cotx)/x
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limx→0(1/sinx - cosx/sinx )/x
limx→0{(1-cosx)/sinx}/x
limx→0{2sin²(x/2) / (2sin(x/2)cos(x/2))/x
limx→0(tan(x/2))/x
limx→0{tan(x/2)/(x/2)}1/2
putting limit.......
since limx→0 tan(x/2)/(x/2) =1
therefore.....
answer is 1/2....
limx→0{(1-cosx)/sinx}/x
limx→0{2sin²(x/2) / (2sin(x/2)cos(x/2))/x
limx→0(tan(x/2))/x
limx→0{tan(x/2)/(x/2)}1/2
putting limit.......
since limx→0 tan(x/2)/(x/2) =1
therefore.....
answer is 1/2....
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