lim x tends to 1 f(x)-f(1)÷x-1
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limx-->1 f(x)-f(1)/x-1
Put x =0
=> 0/0 form
now applying l hospital rule
limx-->1 f'(x) -0/1-0
=> limx-->1 f(x)-f(1)/x-1 = f'(1)
Put x =0
=> 0/0 form
now applying l hospital rule
limx-->1 f'(x) -0/1-0
=> limx-->1 f(x)-f(1)/x-1 = f'(1)
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