Question

lim x tends to +2 x^2 - 5x + 2÷x^3-5x +2

Answer 1

-1/7 should be the answer of the following question

Answer 2

factorise the numerator and denominator
we get
$(x - 2)(x - 3) \div( (x - 2)(x ^{2} + 2x - 1))$
cancelling the x-2
we get
$(x - 3) \div (x ^{2} + 2x - 1)$
and now we can simply put x=2 here and will get the desired result.
$(2 - 3) \div (2 ^{2} + 2 \times 2 - 1) \\ = \: \frac{ - 1}{7}$