lim x tends to e logx-1/x-e
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Lim (x→e ) { logx - 1}/( x -e )
put x = e we see 0/0 comes
so, use L-Hospital rule
differentiate numerator and denominator wrt x
Lim(x→e ) ( 1/x )/( 1 -0)
now put x = e
then 1/e comes
hence,
limit (x→0)(logx-1)/(x -e) = 1/e
put x = e we see 0/0 comes
so, use L-Hospital rule
differentiate numerator and denominator wrt x
Lim(x→e ) ( 1/x )/( 1 -0)
now put x = e
then 1/e comes
hence,
limit (x→0)(logx-1)/(x -e) = 1/e
nazusk:
can you plz differentiate it using l hospital rule
dear ! i differentiate also , did you not see
(logx - 1) differentiate 1/x
( x - e) differentiate 1
then what u want !!!!
can you mark it brainliest
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