Lim (x tends to e) [logx-1]/(x-e)
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(log(x) -1)/(x-e) =log (x/e)/e((x/e)-1)
now using lim (x--->0)log(x+1)/x. =1
as x/e -->1 and x/e -1 -->0
we get 1/e
now using lim (x--->0)log(x+1)/x. =1
as x/e -->1 and x/e -1 -->0
we get 1/e
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