Question

lim xstands to 0 sin4x÷sin2x

Answer 1

Answer:

Step-by-step explanation:2

Answer 2

$limx \: tands \: to \: 0 \: \: \frac{ \sin(4x) }{ \sin(2x) }$
differentiating numerator and denominator with respect to x ( D L hospital's rule)

$limx \: tends \: to \: 0 \: \: \frac{4 \cos(4x) }{2 \cos(2x) }$
$therefore \: \: \frac{4 \cos(0) }{2 \cos(0) }$
$= \frac{4 \times 1}{2 \times 1 } = \frac{2}{1} = 2$



another method is

lim x tends to 0 sin(4x)/sin(2x)

= lim x tends to 0 2sin(2x)cos(2x)/2sin(x)cos(x)

= lim x tends to 0 4sin(x)cos(x)cos(2x)/2sin(x)cos(x)

= lim x tends to 0 4cos(2x)/2

= 4cos(0)/2

= 4/2

= 2
hope it helps...