Math, asked by manavvd401, 2 months ago

limit 0 to Pi /2 integration xsinx

Answers

Answered by s20777bshankar01461

0

Answer:

∫

0

2

π

xsinxdx

=[−xcosx]

0

2

π

+∫

0

2

π

cosxdx

=[−xcosx+sinx]

0

2

π

=[1−0]

=1

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