English, asked by edathilakhila, 6 months ago

limit h tends to zero
 \sqrt{?} (3h \:  + 1 )
plus one divided by h​

Answers

Answered by Anonymous
0

Explanation:

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Answered by rajeshverma4579
0

Answer:

Evaluate limit as h approaches 0 of ((8+h)^(1/3)-2)/h

limh→0

(8+h)

1

3

-2

h

Take the limit of each term.

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1

3

limh→0 1

( limh→0 8+ limh→0 h)

2

3

Evaluate the limits by plugging in 0 for all occurrences of h.

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1

3

1

(8+0)

2

3

Simplify the answer.

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1

12

The result can be shown in multiple forms.

Exact Form:

1

12

Decimal Form:

0.08

Explanation:

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