Question

limit n tends to infinity (1+2/n)^2n =​

Answer 1

here's your answer

To start with, note that limn→∞(1+an)bn=eab . This will almost certainly come up again and again, so you will need to memorise this.

In this question, a=−2 and b=1 , therefore limx→∞(1−2n)n=e−2

Answer 2

Answer:

Step-by-step explanation:

1 ^ infinity

2n(1 + 2/n - 1)

2n (2/n)

4