Question

​​limit of x 3 -7x 2 ​ +15x-9/x 4 -5x 3 +27x-27​ where x tends to 3

Answer 1

lim (x^3-7x^2+15x-9)/(x^4-5x^3+27x-27)
where x tends to 3
first we check by put x=3
we find 0/0
hence this is format of limit
now use differentiation rule in which above and below diffrentiate w.r.t x
lim(3x^2-14x+15)/(4x^3-15x^2+27)
now put x=3
we again find 0/0
again defferentiate w.r.t x
lim (6x-14)/(12x^2-30x)
now put x=3
we find 4/18=2/9 this is finite value
hence 2/9 is answer

Answer 2

Answer:

Step-by-step explanation: