Math, asked by pratikraj69, 1 day ago

limit of x tending to infinity 2^-x * sin(2^x)​

Answers

Answered by neelusingh1288
0

Answer:

Mark me as brantiest answer

Step-by-step explanation:

Limits of sin2xx2 as x approaches infinity

Now sin(x)2 does oscillate as x approaches infinity and therefore a limit does not exist. However it oscillates between the numbers −1 and 1.

Similar questions