Question

limit tends to 0 e(x+h)2-ex2/h​

Answer 1

Answer:limit h->0{e^(x+h)^2-e^(x^2)}/h=limit h->0{e^(x^2+2xh+h^2)-e^(x^2)}/h=e^(x^2) limit h->0{e^(2xh+h^2)-1}/(2xh+h) ×limit h->0( 2xh+h)/h}=e^(x^2)×{limit (2xh+h)->0 e^(2xh+h^2)-1/(2xh+h^2)× limit h->0 2xh+h^2/h}=e^(x^2)×1×2x=2xe^(x^2)(answer)

Step-by-step explanation:

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