Question

Limit X tends to 1 x minus one upon x square minus x minus one upon x cube minus 3 X square + 2 x

Answer 1

$x - {( \frac{1}{x} )}^{2} - x - { (\frac{1}{x}) }^{3} - {3x}^{2} + 2x \\ \\ = > - \frac{1}{ {x}^{2} } - \frac{1}{ {x}^{3} } - 3 {x}^{2} + 2x$