Question

limit x tends to -infinity e^x cos x is ​

Answer 1

Step-by-step explanation:

I want to find the limit of this function by simply using algebraic manipulation. Though I have computed the limit through L' Hospital's method but still I want to compute the limit purely by function's manipulation to yield a form where limit can be applied

limx→0ex−excosxx+sinx

Till now we have been taught basic limits such as limx→0ex−1x=1 and that's why I have been trying to bring such form in this expression.

P.S. I got the current answer by L'Hospital's rule i.e. 0