Limit x tends to pi/2 cotx - tanx/(6x - pi)cube
Answers
Answered by
0
You asked
Let's check the form of limit ,
Put x = π/2
LHS = cotπ/2 - tanπ/2 = 0 - ∞ = -∞
RHS = (6x - π)³ = (6 × π/2 - π)³ = 4π²
LHS/RHS = -∞/4π²≠ form of limit
Hence, line doesn't exist
Let's check the form of limit ,
Put x = π/2
LHS = cotπ/2 - tanπ/2 = 0 - ∞ = -∞
RHS = (6x - π)³ = (6 × π/2 - π)³ = 4π²
LHS/RHS = -∞/4π²≠ form of limit
Hence, line doesn't exist
Similar questions
Accountancy,
7 months ago
English,
7 months ago
Physics,
1 year ago
Math,
1 year ago
Math,
1 year ago