Limit x tends to zero (sin4x+sin2x)÷6x
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Step-by-step explanation:
Lim (sin4x+sin 2x )/6x
x tend to 0
apply L' hospital rule because 0/0 from wil come when x= 0 put in the question
differentiate denominator and numerator with respect to x
Lim. ( 4cos4x +2cos2x)/6 = 4+2/6= 1
x tend to 0
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