limx → 1[(xx – 1) / (xlog(x))]
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Answer:=1^2(1+0) = 1
Step-by-step explanation:
Lim x->1 of {x^x(1+ln x}/(1/x)
= Lim-> 1 of {x^(x+1) (1+ln x)}
= 1^2(1+0) = 1
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