Math, asked by ratnearti, 4 months ago

limx → 1⁡[(xx – 1) / (xlog(x))]​

Answers

Answered by anitamcintyre22
0

Answer:=1^2(1+0) = 1

Step-by-step explanation:

Lim x->1 of {x^x(1+ln x}/(1/x)

= Lim-> 1 of {x^(x+1) (1+ln x)}

= 1^2(1+0) = 1

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