Question

limx→∞
√
(4x2+1
)/(x+1)
​

Answer 1

Answer:

2

Step-by-step explanation:

$\lim_{x \to \infty} \frac{\sqrt{4x^{2} +1} }{x+1} \\= \lim_{x \to \infty} \frac{\sqrt{\frac{4x^{2} +1}{x^{2} } } }{\frac{x+1}{x} }\\\\= \lim_{x \to \infty} \frac{\sqrt{4+\frac{1}{x^{2} } } }{1+\frac{1}{x} }\\\\= \frac{\sqrt{4 + 0} }{1+0} \\\\= 2$