Math, asked by pikachu71, 10 months ago

limx->2 {[(√1+√2+x) +√3 ]/ x+2}

Answers

Answered by debabratajv
1

Step-by-step explanation:

limx->2{[(root over 1+root over 2+root over x+root over 3]/x+2}

= root over1+root over2+ root over3+2 /4

(ans)

Similar questions