Question

limxappproaches0 1-cos5x/1-cos7x

Answer 1

Answer:

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Answer 2

Answer:

lim x - 0, (1-cos5x)/(1 -7x) = 2sin^2(5x/2)/2sin^2(7x/2)

=sin^2(5x/2)/sin^2(7x/2)

=(sin(5x/2).sin(5x/2))/(sin(7x/2).sin(7x/2))

=(5x/2).sin(5x/2)/(5x/2) similarly do for sin7x/2

=(5x/2÷7x/2). 1 lim x to 0 sin5x/2 similarly do for sin7x/2

(5/7).1.0/1.0

=0/0

=infinity