Question

Line 3x+4y=25 touches the circle x^2 +y^2 = 25 at the point

Answer 1

Y= 4; x=3

Get X in terms of y from first eq.

X=(25-4y)/3

Substitute in second eq.

By solving you will get

Y2-8y+16=0

Here you will get y value as 4

Substitute in first eq we will get X value as 3

Answer 2

Hope its usefull....

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